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 Posted by ivi4e at Oct 25, 2011 12:10:09 AM Solving inequality (x+|y|)(x+3)<=0step by step if possibleThank you!

Posted by pskinner at Oct 28, 2011 7:40:19 PM
Re: Solving inequality
 (x+|y|)(x+3)<=0step by step if possibleThank you!

So, one of the factors needs to be positive while the other factor is negative. That's two cases:

x<-|y| and x>-3 (that is, -3<x<|y|)
or
x>-|y| and x<-3 (that is, -|y|<x<-3)
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Principal Skinner

 Posted by chungkshinnn at Nov 21, 2011 6:06:58 AM Re: Solving inequality Is there any mobile application as such some handy application for quick reference or kind of calculator for calculations. ---------------------------------------- Campervan Rental New Zealand

 Posted by clarksammy at Dec 21, 2011 7:25:12 AM Re: Solving inequality Practice will be preferable rather having habit of using calculator. ---------------------------------------- parentline

Posted by MariaFernandes at Feb 3, 2012 1:37:33 AM
Re: Solving inequality

 (x+|y|)(x+3)<=0step by step if possibleThank you!

So, one of the factors needs to be positive while the other factor is negative. That's two cases:

x<-|y| and x>-3 (that is, -3<x<|y|)
or
x>-|y| and x<-3 (that is, -|y|<x<-3)

Can you please be a bit more elaborative? I am not getting it.
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Posted by pskinner at Feb 5, 2012 2:55:02 PM
Re: Solving inequality

 (x+|y|)(x+3)<=0step by step if possibleThank you!

So, one of the factors needs to be positive while the other factor is negative. That's two cases:

x<-|y| and x>-3 (that is, -3<x<|y|)
or
x>-|y| and x<-3 (that is, -|y|<x<-3)

Can you please be a bit more elaborative? I am not getting it.

Draw the vertical line x=-3 as a dashed line. Then draw the line y=x beginning at the origin as a dashed line (in the first quadrant). Finally, draw the line y=-x beginning at the origin as a dashed line (in the fourth quadrant). So, the lines y=x and y=-x meet at the origin in a sideways "V" shape. The area between that sideways "V" shape and the dashed line x=-3 is the graphical solution.

Hope this helps.
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Principal Skinner