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WebGraphing.com Forum » List all forums » Forum: Precalculus and Trigonometry Homework Help » Thread: Help with parabolas and ellipses!!!!! |
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Total posts in this thread: 2 |
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Find the equation of a parabola with its vertex at the origin if its focus is at (4,0). Find the center, vertices, and foci for the ellipse: 9x^2+64y^2=576 |
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Joined: Apr 2, 2005 Posts: 694 Status: Offline |
The general equation of a parabola is: (x-h)^2=4p(y-k), where (h,k) is the vertex and (h,k+p) is the focus. So, in your case, (h,k)=(0,0) meaning that h=0 and k=0. Further, in your case, (h,k+p)=(0,4), so k+p=4 and since k=0, it must be that p=4. The equation is (x-0)^2=4*4(y-0), which simplifies to x^2=16y. ---------------------------------------- Principal Skinner |
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