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WebGraphing.com Forum » List all forums » Forum: Algebra, Pre-Algebra, and Basic Math Homework Help » Thread: Propertiesof exponential and Logarithmic Functions |
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Total posts in this thread: 2 |
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drek232000
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Ok so the quarter is winding down and these questions are getting much harder. I have been really struggling on these couple of questions and would love to see if anyone here can help me. Simplify the following expressions (reduce to a single expnential or a single logarithm) 1. 2^3x+1*4^1-x/4 8^x^2-1 2. log3(x+1)-2log3(x-1)+log3(x^2+x-2) Anyone that could help out even just a little bit would be of great help thank you. |
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pskinner
Joined: Apr 2, 2005 Posts: 797 Status: Offline |
For #1, I assume you mean 2^(3x+1)*4^(1-x/4) 8^(x^2-1) With that in mind, rewrite 4^(1-x/4)=2^2^(1-x/4)=2^(2-x/2) and rewrite 8^(x^2-1)=2^3^(x^2-1)=2^(3x^2-3) Once you have each of the three terms with the same base, you can combine exponents, recalling that moving 2^(3x^2-3) from the denominator to the numerator yields the negative of the exponent: 2^(3-3x^2) and then you just add the exponents and get 2^(sum of the exponents) For #2, rewrite 2log(3(x-1) as log[(3^2)(x-1)^2] log3(x+1)-2log3(x-1)+log3(x^2+x-2) =log[3(x+1)*3(x^2-2)/{(3^2)(x-1)^2)}] ---------------------------------------- Principal Skinner |
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Re: Propertiesof exponential and Logarithmic Functions